Carol A Brown

Age 82
Howey, Florida

Carol A Brown is 82 years old, was born on Saturday, 30th of May 1942 and will celebrate the 83 birthday on May 30. She is currently listed at 25929 San Rafael Ct, Howey, Lake, Florida 34737 and has no known party affiliation. Carol is a female (White, Not Hispanic) and is registered to vote in Lake County since October 17, 2011.

Overview of Carol A Brown

Age: 82

Gender: female

Birth year: 1943

Lives in: Howey, Florida

Carol A Brown's Voting Profile

Registered to vote inLake County

Registered to vote sinceOctober 17, 2011

Party AffiliationNo party affiliation

StatusAct

Precinct21

Precinct Group0

Precinct Split21

Voter ID119182177

Congressional District11

House District32

Senate District12

County Commission0

School Board0

Carol A Brown Address & Maps

Neighbors for Carol A Brown

25921 San Rafael Ct, Howey, Lake, Florida 34737
Republican Party of Florida
25921 San Rafael Ct, Howey, Lake, Florida 34737
No party affiliation
25924 San Rafael Ct, Howey, Lake, Florida 34737
No party affiliation
25924 San Rafael Ct, Howey, Lake, Florida 34737
No party affiliation
25924 San Rafael Ct, Howey, Lake, Florida 34737
No party affiliation
25928 San Rafael Ct, Howey, Lake, Florida 34737
Republican Party of Florida
25928 San Rafael Ct, Howey, Lake, Florida 34737
Republican Party of Florida
25932 San Rafael Ct, Howey, Lake, Florida 34737
Republican Party of Florida
25932 San Rafael Ct, Howey, Lake, Florida 34737
Republican Party of Florida
25933 San Rafael Ct, Howey, Lake, Florida 34737
Republican Party of Florida
25933 San Rafael Ct, Howey, Lake, Florida 34737
Republican Party of Florida
25936 San Rafael Ct, Howey, Lake, Florida 34737
Republican Party of Florida
25936 San Rafael Ct, Howey, Lake, Florida 34737
Republican Party of Florida
25937 San Rafael Ct, Howey, Lake, Florida 34737
Republican Party of Florida
25937 San Rafael Ct, Howey, Lake, Florida 34737
No party affiliation

Other data

Salary: $69,445

Net Worth: $319,826

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